Declaring Constants in ES6

ES6 provides a new way of declaring a constant by using the const keyword. The const keyword creates a read-only reference to a value.

const CONSTANT_NAME = value;Code language: JavaScript (javascript)

By convention, the constant identifiers are in uppercase.

Like the let keyword, the const keyword declares blocked-scope variables. However, the block-scoped variables declared by the const keyword can’t be reassigned.

The variables declared by the let keyword are mutable. It means that you can change their values anytime you want as shown in the following example:

let a = 10;
a = 20;
a = a + 5;
console.log(a); // 25Code language: JavaScript (javascript)

However, variables created by the const keyword are “immutable”. In other words, you can’t reassign them to different values.

If you attempt to reassign a variable declared by the const keyword, you’ll get a TypeError like this:

const RATE = 0.1;
RATE = 0.2; // TypeErrorCode language: JavaScript (javascript)

Unlike the let keyword, you need to initialize the value to the variable declared by the const keyword.

The following example causes a SyntaxError due to missing the initializer in the const variable declaration:

const RED; // SyntaxErrorCode language: JavaScript (javascript)

JavaScript const and Objects

The const keyword ensures that the variable it creates is read-only. However, it doesn’t mean that the actual value to which the const variable reference is immutable. For example:

const person = { age: 20 };
person.age = 30; // OK
console.log(person.age); // 30Code language: JavaScript (javascript)

Even though the person variable is a constant, you can change the value of its property.

However, you cannot reassign a different value to the person constant like this:

person = { age: 40 }; // TypeError
Code language: JavaScript (javascript)

If you want the value of the person object to be immutable, you have to freeze it by using the Object.freeze() method:

const person = Object.freeze({age: 20});
person.age = 30; // TypeErrorCode language: JavaScript (javascript)

Note that Object.freeze() is shallow, meaning that it can freeze the properties of the object, not the objects referenced by the properties.

For example, the company object is constant and frozen.

const company = Object.freeze({
    name: 'ABC corp',
    address: {
        street: 'North 1st street',
        city: 'San Jose',
        state: 'CA',
        zipcode: 95134
    }
});Code language: JavaScript (javascript)

But the company.address object is not immutable, you can add a new property to the company.address object as follows:

company.address.country = 'USA'; // OKCode language: JavaScript (javascript)

JavaScript const and Arrays

Consider the following example:

const colors = ['red'];
colors.push('green');
console.log(colors); // ["red", "green"]

colors.pop();
colors.pop();
console.log(colors); // []

colors = []; // TypeErrorCode language: JavaScript (javascript)

In this example, we declare an array colors that has one element using the const keyword. Then, we can change the array’s elements by adding the green color. However, we cannot reassign the array colors to another array.

JavaScript const in a for loop

ES6 provides a new construct called for...of that allows you to create a loop iterating over iterable objects such as arrays, maps, and sets.

let scores = [75, 80, 95];

for (let score of scores) {
	console.log(score);
}Code language: JavaScript (javascript)

If you don’t intend to modify the score variable inside the loop, you can use the const keyword instead:

let scores = [75, 80, 95];
for (const score of scores) {
    console.log(score);
}Code language: JavaScript (javascript)

In this example, the for...of   creates a new binding for the const keyword in each loop iteration. In other words, a new score constant is created in each iteration.

Notice that the const will not work in an imperative for loop. Trying to use the const keyword to declare a variable in the imperative for loop will result in a TypeError:

for (const i = 0; i < scores.length; i++) { // TypeError
    console.log(scores[i]);
}Code language: JavaScript (javascript)

The reason is that the declaration is only evaluated once before the loop body starts.